OrderedNodeMixin.prev

Returns the previous valued node in the tree.

You should never call this on the leftmost node of the tree as it is assumed that there is a valid previous node.

mixin template OrderedNodeMixin(size_t N)
@property
inout(typeof(this))*
prev
inout
(
)
in { debug assert (&this !is this.index!N.parentmost.index!N.leftmost, "calling prev on _end.leftmost"); }

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