OrderedIndex.opBinaryRight

in operator. Check to see if the given element exists in the container.

Complexity: O(log(n))

  1. bool opBinaryRight(Elem e)
    mixintemplate OrderedIndex(size_t N, bool allowDuplicates, alias KeyFromValue, alias Compare, ThisContainer)
    const
    bool
    opBinaryRight
    (
    string op
    )
    if (
    op == "in"
    )
  2. bool opBinaryRight(K k)

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